2024 Hcf of 1305 4665 6905

Hcf of 1305 4665 6905

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Weblet N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. The sum of digits in N is a. 4 b.5 c.6 d.8 Asked In SSC parkv36 (7 years ago) Unsolved Read Solution (2) Is this Puzzle helpful? (6) (1) Submit Your Solution LCM and HCF Advertisements Read Solution (2) : Please Login to Read Solution. WebHCF and LCM Questions & Answers : The L.C.M of 22, 54, 108, 135 and 198 is ... If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ? A) 6 B) 8 C) 4 D) 9 ...

What is HCF of 13 and 455? - Quora

WebN = H.C.F. of (6905 - 4665), (4665 - 1305), and (6905 - 1305) = H.C.F. of 2240, 3360 and 5600 . HCF of 5600 and 3360: 5600 = 3360 × 1 + 2240 3360 = 2240 × 1 + 1120 2240 = … WebCorrect Option: A We can say that the largest number which when divide the numbers a, b and c give remainders as p, q, r respectively is given by H.C.F. of (a – p), (b – q) and (c – r). The greatest number N = HCF of (1305 – t ), (4665 – t ) and (6905 – t), where t is the remainder = HCF of (4665 – 1305), (6905– 4665) and (6905 – 1305) cpac schedule 2021 live

Let N be the greatest number that will divide 1305, 4665 and 6905 ...

WebA. 4 B. 3 C. 6 D. 5 Solution: If the remainder is same in each case and remainder is not given, HCF of the differences of the numbers is the required greatest number 6905 - 1305 = 5600 6905 - 4665 = 2240 4665 - 1305 = 3360 Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N = HCF of 5600, 2240, 3360 ... http://placementstudy.com/arithmetic-aptitude/3/hcf-and-lcm/24 WebHighest Common Factor of 4665, 1305, 6905 using Euclid's algorithm. HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily … cpa crossings llc

If N is the greatest number that will divide 1305, 4665 and 6905 ...

HCF Calculator Find the Highest Common Factor of given …

WebAug 22, 2024 · If the remainder is same in each case and remainder is not given, HCF of the differences of the numbers is the required greatest number 6905 - 1305 = 5600 6905 - 4665 = 2240 4665 - 1305 = 3360 Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N = HCF of 5600, 2240, 3360 = 1120 Sum of digits in N WebLet N be the largest integer that divides 1305, 4665, and 6905 without leaving the same residual in each case. Then in N, the total of the digits is: a. 4 b. 5 c. 6 d. 8 5. The greatest four-digit number that is divisible by 15, 25, 40, and 75 is: a. 9000 b. 9400 c. 9600 d. 9800 6. The sum of two integers equals 4107. cpac replaysWebHCF & LCM. 96 N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N? A. 4. B. 3. C. 6. D. 5 Answer Report . Discuss. 97 ... cpa crockett texas

"WebDetailed Solution for Practice Test: HCF & LCM - Question 4. N = greatest number that will divide 105, 4665 and 6905 leaving the same remainder in each case. ⇒ N = H.C.F. of … " - Hcf of 1305 4665 6905

Hcf of 1305 4665 6905

Web1) Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case Then sum of the digits in N is : A) 4 B) 5 C) 6 D) 8 Answer: Option A Explanation: N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) = H.C.F. of 3360, 2240 and 5600 = 1120. Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4 Note: WebJun 22, 2024 · Aishwarya06. Since the remainder is same in each case, we will use the following formula-. H.C.F (x, y, z)= H.C.F of (x -y), (y- z), ( z-x) So, let's take out the …

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WebJul 2, 2024 · 4665 - 1305 = 3360 6905 - 4665 = 2240 6905 - 1305 = 5600 HCF of 3360, 2240 and 5600 = 1120 Then sum of the digits in N = 1 + 1 + 2 + 0 = 4 ∴ The sum of the digits in N is 4 Download Solution PDF Latest Odisha … WebN = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) = H.C.F. of 3360, 2240 and 5600 = 1120. Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4. Note: We are taking hcf of (4665 - …

WebHighest Common Factor of 1305, 4665, 6905 using Euclid's algorithm. HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily … WebApr 7, 2024 · The given numbers are 1305, 4665 and 6905. We have to find the greatest number N that will divide 1305, 4665 and 6905 leaving the same remainder. The greatest …

WebMar 15, 2024 · The HCF and LCM of the two numbers are 13 and 455 respectively. If one of the numbers lies between 75 and 125, then, that numbers are: (a) 78 (b) 91 (c) 104 (d) 117. ... Let N be the greatest number that will divide 1305, 4665, and 6905 leaving the same remainder in each case. Then, the sum of the digits in N is: (a) 4 (b) 5 (c) 6 Web135 = 3 × 3 × 3 × 5. Find the prime factorization of 405. 405 = 3 × 3 × 3 × 3 × 5. To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 3 × 3 × 3 …

WebN = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) = H.C.F. of 3360, 2240 and 5600 = 1120. Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4 Subject: HCF and LCM - Quantitative Aptitude - Arithmetic Ability Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE Job Role: Bank Clerk , Bank PO Related Questions Q: Consider a two-digit number.

WebStep 1: Find the prime factors for 40 and 60, The prime factorization of 40 is 2 x 5. The prime factorization of 60 is 2 x 3 x 5. Step 2: List out the highest number of common prime factors of 40 and 60 ie., 2 x 2 x 5. Step 3: Now, on multiplying the common prime factors we will get the HCF of two numbers. 2 * 2 * 5 = 40. cpac schedule dallas txWebWhat is the HCF of a 2 b 4 + 2 a 2 b 2 and (ab) 7 - 4a 2 b 2? Options A. ab B. a2 b3 C. a2 b2 D. a3 b2 Show Answer Scratch Pad Discuss 7. Find the largest number which divides 1305, 4665 and 6905 leaving same remainder in each case. Also, find the common Remainder. Options A. 1210, 158 B. 1120, 158 C. 1120, 185 D. 1210, 185 Show Answer … cpac schofieldWebJun 22, 2024 · So, let's take out the H.C.F of 1305, 4665 and 6905 (leaving the same remainder) = H.C.F of (4665 - 1305), ( 6905- 4665) and ( 6905- 1305) = H.c.f of 3360, 2240 and 5600 which is= 1120. Sum of digits of 1120= (1+1+2+0)= 4. Answer=4. Find Math textbook solutions? Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 … cpac seating mapWebIt will be the HCF(3360, 5600, 2240) = 1120 Sum of digit= 1+1+2+0=4. Suggest Corrections. 0. Similar questions. Q. ... Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. The sum of the digits in N is: Q. cpac schedule 2022 texasWebLet N be the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder in each case. Then, sum of the digits in N is : (1) 4 (2) 5 (3) 6 (4) 8 10. What is the greatest number that will divide 307 and 330 leaving remainder 3 and 7 respectively? cpa cryptocurrencyWebLet N be the greatest number that divides 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: a) 4 b) 5 c) 6 d) 8 Asked In TCS shikha (8 years ago) Solved harvinder Read Solution (2) Is this Puzzle helpful? (12) (3) Submit Your Solution undefined Advertisements Read Solution (2) : disney vacation club cruise perksWebQuestion: Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is . Solution: N = H.C.F. of … disney vacation club discount raglan road